1. e4 e6 2. d4 d5 3. Nc3 Bb4 4. e5 Ne7 5. a3 Bxc3+ 6. bxc3 c5 7. Qg4 cxd4 8. Qxg7 Rg8 9. Qxh7 Qc7 10. Ne2 dxc3 11. f4 Nbc6 12. Qd3 d4 13. Nxd4 Nxd4 14. Qxd4 Bd7 15. Rg1 Nf5 16. Qf2 Qc6 17. Bd3 Qd5 18. Rb1 Bc6 19. Rb3 O-O-O 20. Rxc3 Kb8 21. g4 Nd4 22. Rg3 Qh1+ 23. Bf1 Bb5??

Theory continues 23... b6! and Black is thought to have full compensation for the two pawns.

24. Qg2 Qxg2 25. Rxg2 Bxf1 26. Kxf1 Nb5 27. Rd3 Rxd3 28. cxd3 Rh8 29. f5 exf5 30. gxf5 Nd4 31. Rg5 Rxh2 32. Bf4 Rh4 33. Bg3 Rh7 34. e6+

1-0

Source(s): TWIC 1240.

Event information: Tournament report.