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rnbqkbnr
pppppppp
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PPPPPPPP
RNBQKBNR

 

Start Back 5 Back 1 Forward 1 Forward 5 End Flip Auto Variations controls



 
Harding, Tim   –   Reynolds, Pat
c, 1896 (1807) 1748 (1630)
 
A57 Irish 65+ Championship 2024 (6.4) 2024.01.07

1. d4 Nf6 2. c4 c5 3. d5 b5 4. cxb5 e6 5. Nc3 exd5 6. Nxd5 Bb7 7. e4 a6 8. a4 d6 9. Bc4 Nbd7 10. Nf3 Nxd5 11. bxa6 Bxa6 12. Qxd5 Bxc4 13. Qxc4 Be7 14. O-O O-O 15. Bd2 Nf6 16. Bc3 Qd7 17. Rfe1 Qc6 18. Nd4 Qd7 19. Nf5 Rfe8 20. Nxe7+ Qxe7 21. e5 Nd7 22. exd6 Qxd6 23. a5 h6 24. Rad1 Rxe1+ 25. Rxe1 Nf8 26. Qe4 Rd8 27. g3 Ne6 28. Qe5 Qc6 29. Qe4 Qd6 30. b4 cxb4 31. Bxb4 Qa6 32. Bc3 Rd3 33. Qe5 Qc4 34. Re3 Rd5 35. Qb8+ Rd8 36. Qb4 Rd1+ 37. Re1 Qd5 38. Rxd1 Qxd1+ 39. Kg2 Qd5+ 40. f3 Ng5 41. Qb8+ Kh7 42. Qf4 Qa2+ 43. Qd2 Qe6 44. Qd3+ Kg8 45. g4 Qa2+ 46. Kg3 Ne6 47. Qb5 Qc2 48. Qe8+ Kh7 49. Qxf7 Qxc3 50. Qxe6 Qxa5 51. Qf5+! Qxf5 52. gxf5 Kg8 53. Kf4 Kf7 54. Ke5 Ke7 55. h4 Kf7 56. h5 Ke7 57. f6+ gxf6+ 58. Kf5 Kf7 59. f4 Ke7 60. Kg6 f5 61. Kxf5 Kf7 62. Ke5 Ke7 63. f5 Kf7 64. f6 Kf8 65. Kf4 Kg8 66. Ke5

Black must be able to meet Kf5 with Kf7, and Ke6 with Ke8, and therefore must be able to meet Ke5 with Kf8. White therefore wins if he can reach the diagrammed position with Black to move. Here 66. Ke4 Kf8 67. Ke5 is simplest.

66... Kf8 67. Ke6 Ke8 68. f7+??

Any other move preserves the win.

68... Kf8 69. Kf6

1/2-1/2


Event information: Tournament report.

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